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When we fetch a stand-alone personal key, make sure AP-Actor matches key owner

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If the key we fetched is a shared key, the only way to determine the actor to
which the signature applies is to read the HTTP header ActivityPub-Actor. But
if it's a personal key, we can detect the actor by checking the key's owner
field. Still, if that actor header is provided, we now compare it to the key
owner and make sure they're identical.

When fetching a key that is embedded in the actor document, we were already
comparing the actor ID with the actor header, so that part didn't require
changes.
This commit is contained in:
fr33domlover 2019-02-17 00:14:05 +00:00
parent bf56ebf158
commit fa5c509a25
1 changed files with 12 additions and 7 deletions
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19
src/Web/ActivityPub.hs
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@ -54,6 +54,7 @@ import Data.Aeson.Types (Parser)
import Data.Bifunctor (bimap, first)
import Data.Bitraversable (bitraverse)
import Data.ByteString (ByteString)
import Data.Foldable (for_)
import Data.List.NonEmpty (NonEmpty)
import Data.PEM
import Data.Semigroup (Endo)
@ -429,7 +430,13 @@ fetchKey manager sigAlgo muActor uKey = runExceptT $ do
then case muActor of
Nothing -> throwE "Key is shared but actor header not specified!"
Just u -> return u
else return $ publicKeyOwner pkey
else do
let owner = publicKeyOwner pkey
for_ muActor $ \ u ->
if owner == u
then return ()
else throwE "Key's owner doesn't match actor header"
return owner
actor <- fetch uActor
let PublicKeySet k1 mk2 = actorPublicKeys actor
match (Left uri) = uri == uKey
@ -441,12 +448,10 @@ fetchKey manager sigAlgo muActor uKey = runExceptT $ do
if actorId actor == uKey { furiFragment = "" }
then return ()
else throwE "Actor ID doesn't match the keyid URI we fetched"
case muActor of
Nothing -> return ()
Just u ->
if actorId actor == u
then return ()
else throwE "Key's owner doesn't match actor header"
for_ muActor $ \ u ->
if actorId actor == u
then return ()
else throwE "Key's owner doesn't match actor header"
let PublicKeySet k1 mk2 = actorPublicKeys actor
match (Left _) = Nothing
match (Right pk) =